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if (isNaN(food)){
isRunning = false;
break;
}
if (food === 'apple') {
size='1 small (4 oz.)';
calories='80 kcl';
}else if (food ==='banana') {
size='1 medium (6 oz.)';
calories='101 kcl';
}else if (food ==='grape') {
size='each';
calories='2 kcl';
}
Anyone spot the mistake of this loop?
Thanks for the people who answered my enquries
food = 'apple' assigns the value apple to the variable food. What you want to use for comparison, is the == operator, which compares food and 'apple'.
Change the if condition expression with “==“ i.e comparison operator instead of “=“ i.e. assignment operator.
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I've was given this is a multiple choice JS question. I said [], I just wanted to check if this is correct and if not why?
Consider this if statement:
if (loggedIn) {
body_classes = ["user-active"];
}
Which pair of characters in this code is optional?
""
()
{}
[]
The optional characters are the braces {}
if (loggedIn) {
body_classes = ["user-active"];
}
is the same as
if (loggedIn)
body_classes = ["user-active"];
If you remove the square brackets then body_classes becomes a string rather than an array.
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I have a purple button. It becomes green onclick, even if in the if statement instead of purple I wrote Yellow.
Then it remains green, although the else if statement should make it purple again onclick.
What's wrong with my code?
`var m = document.getElementById ("buttonanimation");
function changecolor(){
if (m.style.backgroundColor="yellow"){
m.style.backgroundColor="green";
} else if (m.style.backgroundColor="green"){
m.style.backgroundColor="purple";
}
}`
This symbol = is the assignment, not the comparison. if (m.style.backgroundColor="yellow") should be if (m.style.backgroundColor === "yellow").
use comparison operator if (m.style.backgroundColor==="yellow") instead of if (m.style.backgroundColor="yellow")
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I'm trying to take a string and check whether or not it contains a lowercase letter or number, and then if so push that letter or number to an array.
for(let i = 0; i < datearg.length; i++)
{
log.info(datearg.charAt(i));
if(/[a-z]/.test(datearg.charAt(i))) letter_num++; letters.push(datearg.charAt(i));
if(/[0-9]/.test(datearg.charAt(i))) number_num++; numbers.push(datearg.charAt(i));
}
However, both if statements always evaluate to true and the arrays end up containing every single character in datearg. Anyone know why?
if(/[a-z]/.test(datearg.charAt(i))) letter_num++; letters.push(datearg.charAt(i));
is equivalent to
if(/[a-z]/.test(datearg.charAt(i))) { letter_num++; }
letters.push(datearg.charAt(i));
i.e. push is not conditional. This is the primary reason why many style guides heavily discourage control structures without braces (which only take a single statement).
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I'm creating a site and i needed to do some js. I'm not that good with it but tought i would figer it out. Not. I created a for loop but it does not run.
function order(user,product){
var index;
for(var i = 0; i<users.lenght; i++){
if(user == users[i]){
index = i;
break;
}
}
var budget = budgets[index];
alert(budget);
}
the creation of the users and budgets arrays are done with php and after checking with alert() it was how it should be.
Can anyone help me please?
lenght is spelt length. The misspelt property does not exist, so it undefined, which is equivalent to 0.
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I want a loop that starts with i=100, and decrements by 5 on each iteration. However, this produces an error:
for(var i=100;i>=1;i-5)
{
document.write(i+"<br />");
}
But 'i=i-5' works:
for(var i=100;i>=1;i=i-5)
{
document.write(i+"<br />");
}
Why?
The question is how we can assign a variable to a variable i=i-5.I go the question answered I taught "i=i-5" was a expression the value of i variable is i-5 and no calculation happen its just a stable variable.
The answer is that it is taking a the i value and subtracting it by 5 and not assigning.
If you just write i - 5, there is no left-hand variable, which means there is nothing which is taking the value of i and subtracting it by 5. If you write i = i - 5 then you will decrement 5 since you now have a left-hand variable.